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8x^2-98x+571=5x^2-50x+379
We move all terms to the left:
8x^2-98x+571-(5x^2-50x+379)=0
We get rid of parentheses
8x^2-5x^2-98x+50x-379+571=0
We add all the numbers together, and all the variables
3x^2-48x+192=0
a = 3; b = -48; c = +192;
Δ = b2-4ac
Δ = -482-4·3·192
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{48}{6}=8$
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